(ii) tan 18° + tan 27° + tan 18°. tan 27° = 1
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2
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True
Step-by-step explanation:
We know,
⇒ tan45° = 1
⇒ tan( 18° + 27° ) = 1
We know, tan( A + B ) = [ tanA + tanB ] / ( 1 - tanA.tanB )
⇒ [ tan18° + tan27° ] / [ 1 - tan18°.tan27° ] = 1
⇒ tan18° + tan27° = 1( 1 - tan18°.tan27° )
⇒ tan18° + tan27° = 1 - tan18°.tan27°
⇒ tan18° + tan27° + tan18°.tan27° = 1
Hence proved
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