Question

(ii) tan x + cot x = 2.
Find general solution​

Answer 1

Step-by-step explanation:

tanx+cotx=2

tanx+1tanx=2

tan2x+1=2tanx

tan2x−2tanx+1=0

tan2x−tanx−tanx+1=0

tanx(tanx−1)−1(tanx−1)=0

tanx−1=0

tanx=1

tanx=tanπ4

x=nπ+π4

x=4nπ+π4

x=(4n+1)π4

n∈Z

Answer 2

may this answer will help yiu