Question

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ii) tan x + tan 2x + tan x tan 2x=1​

Answer 1

Answer:tanx+tan2x+tanxtan2x=1

tanx+tan2x = 1 - tanxtan2x

(tanx+tan2x)/(1 - tanxtan2x) = 1

tan3x = 1

3x = π/4 + nπ, n = 0, ±1, ±2, ...

x = π/12 + nπ/3

= π/12(1 + 4n)

Step-by-step explanation: