Question

(ii) The area of the rhombus ABCD as shown in the fig.
(a) 2016 cm
(c) 4032 cm
(b)8190 cm
(d) 3120 cm
​

Answer 1

Answer: 2016

Step-by-step explanation:

area of ABCD = 4* area of one triangle (due to symmetry)

   area of one triangle = base *height/2

 for triangle AOB

height= OB = 63

Base = $OA = \sqrt{AB^{2}-OB^{2} }$  from pythogorous theoram

   $OA= \sqrt{65^{2}-63^{2} }$

        OA= 16

hence area of ABCD =4* 16*63/2 =2016