(ii) The coach of a cricket team buys 7 bats and 6 balls for Rs 3800. Later, she buys 3
bats and 5 balls for Rs 1750. Find the cost of each bat and each ball.
Answers
Step-by-step explanation:
Let the cost of each bat be Rs. x and cost of each ball be Rs. y
Now as per the question
First he buys 7 bat and 6 balls for Rs. 3800
7x+6y=3800...(1)
Later he buys 3 bats and 5 balls for Rs. 1750
3x+5y=1750...(2)
Now using substitution method from eq2
5y=1750−3x
⇒y=51750−3x
Now putting value of y in eq1
⇒7x+56(1750−3x)=3800
⇒35x+10500−18x=19000
⇒17x=8500
⇒x=500
Now putting value of x in eq2
⇒3×500+5y=1750
⇒1500+5y=1750
⇒5y=1750−1500
⇒5y=250
⇒y=50
Hence each bat cost = Rs. 500 and each ball cost = Rs. 50
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ANSWER:
One bat = ₹ 500
One ball = ₹ 50
GIVEN:
7 bats and 6 balls = ₹ 3,800
3 bats and 5 balls = ₹ 1,750
ASSUMPTION:
Let number of bats be x
Let the number of balls be y
TO FIND:
Cost of each ball and bat.
EXPLANATION:
★ 7x + 6y = 3800 -----------> 1
★ 3x + 5y = 1750 ------------> 2
Multiply equation 1 by 3 and equation 2 by 7
Substitute y = 50 in equation 2
3x + 250 = 1750
3x = 1500
x = 500