Question

ii. The four angles of a quadrilateral are 2(x - 10)°. (x + 30)°, (x + 50°) and 2x. Find all
the four angles.​

Answer 1

Answer:

answer for the given problem is given

Answer 2

Answer:

80°, 80°, 100°, 100°

Step-by-step explanation:

sum of angles of a quadrilateral is 360°

2(x - 10)° + (x + 30)° + (x + 50°) +  2x.= 360° (opening the bracket)

2x-20° + x+30° + x+50° + 2x= 360°

2x + x + x + 2x - 20° + 30° + 50°= 360° (rearranging the terms)

6x + 60°= 360°

6x= 360°-60°

6x= 300°

x=3 00/6

x= 50°

substitute the value of x in all angles

2(x-10)°= 2(50-10)°= 80°

(x+30)= (50+30)°= 80°

(x+50)°= (50+50)°= 100°

2x= 2*50= 100°

thus the angles are 80°, 80°, 100°, 100°