(ii) The mass of m2 was reduced to 50% and the force exerted by m1 on m2 was found to be 20 N, what will be the force exerted by m2 on m1 ?
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same force 20N
why I choose 20N here is the reason
first of all from the question they said mass m2 reduced to 50% nearly half of the mass after that M1 exerts a force on m2 from now you understand I hope so
after that same m2 exerts a force on M1
according to Newton third law
every action there is equal and opposite reaction from this I conclude that
the force exerted by the mass m2 on M1 is 20N in opposite direction
they given 50% reduced mass m2 to confuse you
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