Question

(ii)
The orbital speed (V) of the satellite moving in an orbit that is at a height h
above the surface of the earth is equal to :


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Answer 1

Answer:

2

_

3

Explanation:

Orbital velocity of satellite at height h above the earth surface

RE is the earth radius 

⇒v0=(RE+h)GM=RE+hgRE2

Orbital velocity just above the earth surface 

⇒v0=REgRE2=gRE   (∵h=0)

Orbital velocity at height of half of the earth surface h=21RE

⇒v1=RE+21REgRE2=32gRE