Question

(ii) The probability density function of
a variable X is
3
X 0 1 1 2
4 5 6
P(X): k 3k 5k 7k 9k 11k 13k
Find P(X<4), P (X >5),
P(3< X <6). Here P(X) is a
probability density function.
​

Answer 1

Answer:

random variable X has the following probability distribution:

X=x 0 1 2 3 4 5 6

P(X=x) k 3k 5k 7k 9k 11k 13k

(a) Find k

(b) Find P(0<X<4)

(c) Obtain cumulative distribution function (c.d.f) of X.