Question

(ii) The product of two consecutive positive integers is 306. We need to find the
integers.
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Answer 1

Answer:

Let integers be n and (n+1)

$n(n+1)=306$

$n²+n−306=0$

$(n+17)(n−16)=0$

Therefore, n=16 and integers are 16 and 17.

hope it's helpful

Answer 2

ANSWER

Let first integer be x

second integer be x+1

now solve

$x(x + 1) = 306$

${x}^{2} + x - 306 = 0$

${x}^{2} + 18x - 17x - 306 = 0$

$x(x + 18) - 17(x + 18) = 0$

$(x - 17)(x + 18) = 0$

$x = 17 \: and \: x = - 18$

we take +ve value as product is given in positive.

hence, first integer be 17

second integer be x+1 =18

Hope it helps you

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