Question

(ii) The speed and time graph of a car is given below. Using the data and the graph, calculate
the total distance covered by the car:
30
25
20
D
15
peed in m/s) 10
5
10
30
40
(a) 1250m
(b) 875m
(c) 1500m
(d) 1870m

Answer 1

Answer:

a)

The total number of divisions on horizontal axis for 2 s is 5.

The total number of divisions on vertical axis for 2 m/s is 3.

The total displacement of the car during these two seconds will be given as the area under all these squares.

The area under the (3×5) squares is given as:

A

15

=2×2 = 4

So, the area under one small square is :

A

1

=

15

4

Now, the area under the graph for 4 sec is:

the number of squares under the graph is :

n=57 small squares + 6 half small squares

So, total number of squares =60.

So, the distance traveled by the car is the area under the curve.

S=60×

15

4

S=16 m

(b)

The car moves under the uniform motion after the instant t=6 s because after this instant, the speed of the car becomes constant.

Explanation:

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