Question

(ii) The sum of an integer and twice the next integer is 41. Find the two integers, ​

Answer 1

${ \underline {\bf{Solution:}}}$

$\tt{Let,first \: integer \: be \: x \: So, second \: integer \: is \: x + 1}$

$\tt{According \: to \: question,}$

$\tt{x + 2(x + 1) = 41}$

$\tt{3x + 2 = 41}$

$\tt{X=13}$

$\tt{Hence,}$

$\tt{First \: integer \: is = 13 }$

$\tt{And, second \: is = 14}$