(ii) Trace the parabola x2 = 5y.
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......................
Answered by
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Answer:
given, x^2 = 5y
=> y = x^2/5
vertex = (0 ,0)
focus = (0 , 5/4)
axis of symmetry x=0
directrix y= - 5/4
y | x
-2 | 4/5
-1 | 1
0 | 0
1 | 1/5
2 | 4/5
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