Question

ii)Two charges of LDC each are placed to one meter apart in free space
The force between them will be
a)1.0 N
b)9x10°N
c)9x10°N
d)10N
iii) [L'M'T? Jis the dimensional formula for
a)Velocity
b)Acceleration
c)Force
d)Work
iv)For the vectors to be equal , they should have the
a)same magnitude
b)Same direction
c)Same magnitude and direction
d) Same magnitude but onposite direction​

Answer 1

Explanation:

I hope this is the correct answer

Answer 2

Explanation:

1)

Given :

q1 = 1 C

q2 = 1 C

r = 1 m

To find :

F =?  

Explanation:

F =  $\displaystyle \frac{k \ q1 \ q2}{r^2}$

F = $\frac {9 \times 10^9 \times 1 \times 1} {1^2}$

F = 9 ×$\mathbf {10^9}$ N

2)

[$L^1M^1T^{-2$] is the dimension of force.

3)

Vector is the quantity having magnitude and direction.

For equal vectors, they must have  the same magnitude and direction