Question

ii)
v)
What are the dimensions of the quantity l√l/g, 1 being the length and g the
acceleration due to gravity?
Nuclear r
the mass
16 A1/3 m​

Answer 1

Answer:

dimension of length , l = [L]

dimension of acceleration due to gravity, g = [LT-²]

given expression is l\sqrt{\frac{l}{g}

so, dimension of l\sqrt{\frac{l}{g}}l

g

l

=\textbf{dimension of l}\times\sqrt{\frac{\textbf{ dimension of l}}{\textbf{dimension of g}}}=dimension of l×

dimension of g

dimension of l

= [L]\sqrt{\frac{[L]}{[LT^{-2}]}}=[L]

[LT

−2

]

[L]

= [L]\sqrt{[T^2]}=[L]

[T

2

]

= [LT]

so, dimension of l\sqrt{\frac{l}{g}}l

g

l

is [LT]