Question

(ii) What is the perpendicular distance between the force and the turning point if a force
of 25 N produces a moment of force of 12.5 Nm?
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Answer 1

Answer:

F=525N

τ=420N−m

Moment of force

=Force× Perpendicular distance

∴420N−m=525N× Perpendicular distance.

∴ Perpendicular distance

=525420=0.8m

0.8 m is the shortest distance between the point of application of force and the turning point.

Explanation:

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