(ii) What is the perpendicular distance between the force and the turning point if a force
of 25 N produces a moment of force of 12.5 Nm?
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Answer:
F=525N
τ=420N−m
Moment of force
=Force× Perpendicular distance
∴420N−m=525N× Perpendicular distance.
∴ Perpendicular distance
=525420=0.8m
0.8 m is the shortest distance between the point of application of force and the turning point.
Explanation:
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