ii. What is the smallest number by which 17496 must be divided so that the quotient is a
perfect cube?
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Answer:
the number should be divided by 3
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the smallest number by which 17496 must be divided , so that the quotient is a perfect cube
let smallest number be x
and quotient number be y3
so, 17496/x which gives 0 as remainder and y3 as quotient
so, factors of 17496=2×2×2×3×3×3×3×3×3×3
no of 2′ s are 3
no of 3 's are 7
so, factors of 17496=23×33×33×3=(2×3×3)3×3
so, smallest number is x=3
y3=(2×3×3)3
y=18
the perfect cube is y3=183 cube root of 183=18
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