Question

(ii) What is the sum of first n natural numbers?​

Answer 1

Answer:

The formula to get the sum of n natural numbers is given below:

$Sn = \frac{n}{2} (2a + (n - 1)d) \\ where \: \: a = first \: term \\ d = difference. \\ \\ so \: \: \: \: Sn = \frac{n}{2} (2 \times 1 + (n - 1) \times 1) \\ Sn = \frac{n}{2} (2 + 1 \times (n - 1) \\ Sn = \frac{n}{2} (2 + n - 1) \\ Sn = \frac{n}{2} (1 + n) \\ Sn = \frac{n + n {}^{2} }{2}$

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