ii) What is the value of k, for which the simultaneous equations 2x+3y=8
and 6x-ky = 24 have infinitely many solutions ?
a) 9 b) -6 c) 6 d) -9
Answers
Answered by
10
Answer:
Answer is 9
Step-by-step explanation:
2x + 3y = 8 6x + ky = 24
a¹ = 2 b¹ = 3 c¹ = 8
a² = 6 b² = k c² = 24
have infinitely many solutions
a¹ = b¹ = c¹
a² b² c²
2 = 3 = 8
6 k 24
2 = 3
6 k
2k = 18
k = 18/2
k = 9
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