Math, asked by ashishkasture, 4 months ago

ii) What is the value of k, for which the simultaneous equations 2x+3y=8

and 6x-ky = 24 have infinitely many solutions ?

a) 9 b) -6 c) 6 d) -9​

Answers

Answered by virendrachaudhary056
10

Answer:

Answer is 9

Step-by-step explanation:

2x + 3y = 8 6x + ky = 24

a¹ = 2 b¹ = 3 c¹ = 8

a² = 6 b² = k c² = 24

have infinitely many solutions

= b¹ =

a² b² c²

2 = 3 = 8

6 k 24

2 = 3

6 k

2k = 18

k = 18/2

k = 9

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