Question

(ii) What volume of CO, measured at 20°C and 720 torr pressure will be produced by the reaction between 200 gm of Na2CO3 and HCI
*Na2CO3 + HCI ---- 2NaCl + CO2 + H2O​

Answer 1

Explanation:

Molecular mass of Na2CO3= 106

so 106 gm na2co3 produces 22.4L co2 at ntp

200g produces 22.4*200/106=42.26L at ntp

now use p1v1/t1=p2v2/t2

p1=720

v1 ?

t1 293k

p2 760 torr

v2 42.26

t2 273k

put the values in above equation and get v1

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