Question

ii) What will be the minimum pressure required to compress 750 dm3 of air at 4 bar to 500 dm3 at

Answer 1

According to ideal gas equation, P1V1=P2V2

Here P1=1bar,V1=500dm3,V2=200dm3

Then P2=2001×500=2.5bar 

Answer 2

Explanation:

According to ideal gas equation, P1V1=P2V2

Here P1 =1bar,V1=500dm^3 ,V2=200dm^3

Then P2 =1×500=2.5bar

200

I hope this answer will help you....