(ii) Which flower bed has least area ?
(iii) What is the perimeter of vidyalaya
park ?
(iv) What is cost of planting Jasmine
flower in circular flower bed if it
costs Rs 8 /m2
Answers
2. AREA OF PERIMETER 3.46m² HAS LEAST AREA
3. AREA OF PERIMETER PARK = L× B
= 55× 42
= 2310m²
4. AREA OF CIRCULAR FLOWER BED =
= πr²
= 22/7 × 1.05 × 1.05
= 3.46m²
= 1 m = 8 RS
= 3.46m² = 3.46m²×8
= 27.68 Rs
HENCE : 27.68 Rs COST OF PLANTING JASMINE
FLOWERS
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Answer i) :-
→ Area of ∆ = (1/2) * Base * height = (1/2) * 2 * 3.5 = 3.5 m².
→ Area of square = (side)² = (2.5)² = 6.25 m².
therefore, Square bed has more area than triangle.
Answer ii) :-
→ Area of circle = πr² = (22/7) * 2.1 * 2.1 = 22 * 0.3 * 2.1 = 13.86m².
→ Area of trapezium = (1/2)(sum of parallel sides) * height = (1/2) * (2 + 3) * 1.5 = (1/2) * 5 * 1.5 = 2.5 * 1.5 = 3.75 m².
since ,
→ 3.5 < 3.75 < 6.25 < 13.86 .
→ ∆ < trapezium < square < circle .
therefore, triangular flower bed has least area.
Answer iii) :-
→ Perimeter of vidyalaya park = 2(L + B) = 2(55 + 42) = 2 * 97 = 194 m (Ans.)
Answer iv) :-
→ Cost of planting Jasmine flower in circular flower bed = Rate / m² * Area of circular flower bed = 8 * 13.86 = Rs.110.88 (Ans.)
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