Question

ii) Which identify can be used to find the value of (99) ?
a) (a-b)²=a² - 2ab + b²
(c) (a + b)² = a² + 2ab + b²
b) a² - b² = (a+b) (a-b) = a² - b²
(d) (x + a) (x + b) = x² + (a+b)x + ab​

Answer 1

99 = 100-1 =10²-1²

so answer is b

a²-b² = (a+b)(a-b)

Answer 2

Answer:

(a)

step by step explaination:

(100-1)²

using the identity (a-b)²

(100-1)²= 100²-2×100×1+1²

= 10000-200+1

=9801

hope it helps!!if so mark the brainliest pls