Question

ii. Write the mathematical relation between ∆H and ∆U during formation of one mole of CO2 under standard

conditions.​

Answer 1

Answer:

∆H=∆U

Explanation:

We know that, ∆H=  ∆U+ ∆nRT

Where, ∆n= Total no. of gaseous molecules of the product - Total no. of gaseous molecules of the reactant

C(s) + O2(g) = CO2(g)

Here, ∆n= 0

Therefore, ∆H=∆U

Answer 2

Answer:



Explanation:

Formation of one mole of CO2 under standard conditions:

C(s)+O2(g)---->CO2(g)

Delta ng=moles of product gases - moles of reactant gases

Delta ng=1-1=0

Now,Delta H=Delta U+Delta ngRT

Delta H=Delta U+0×RT

therefore, Delta H=Delta U