Question

(ii) (x - 1) is a factor of 2x4 + 9x3 + 6x2 – 11x – 6.​

Answer 1

Answer:

x-1

x=1

Substitute x for 1

2(1)4+9(1)3+6(1)2-11(1)-6

=8+18+12-11-6

=19

Hence it's not a factor

Answer 2

Answer:

Step-by-step explanation: p (x) = 2x^4 + 9x^3 + 6x^2 - 11x - 6

g (x) = x - 1

to determine the zero of g(x)

g(x) = 0

x - 1 = 0

x = 1

by remainder theorem

p(x) = 0

p(1) = 2 × (1)∧4 + 9 × (1)∧3 + 6 × (1)∧2 - 11 × 1 - 6

p(x) = 2 × 1 + 9 × 1 + 6 × 1 - 11 × 1 - 6

p(x) = 2 + 9 + 6 - 11  - 6

p(x) = 17 - 17

p(x) = 0

since the remainder is zero g(x) is a factor of p(x).