Question

ii) (x+1) (x- 2) + x=0

Answer 1

✪|| Solution ||✪

( x + 1 ) ( x - 2 ) + x = 0

=> x + 1 × x - 2 + x = 0

=> x² + x - 2x - 2 + x = 0

=> x² - x - 2 = 0

=> x² - x = 0 + 2

=> x² - x = 2

=> x² = 2 + x

=> x = $\sqrt{2 + x}$

The value of x is √2+x

Answer 2

Step-by-step explanation:

first find it as a quadratic equation

that is

${x}^{2} + x - 2x - 2 \\ \\ x(x + 1) - 2(x + 1) \\ \\ (x + 1)(x - 2) \: \\ \\ the \: roots \: of \: the \: equation \: are - 1 \: 2$

the roots of this equation are 2;-1

I hope this answer may help you