(ii) x-^2 + 2x-^1 +4
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Understanding the question as 2^{2x+1} = 4^{2x-1}2
2x+1
=4
2x−1
⇒2^{2x+1} = 2^{2*(2x-1)}2
2x+1
=2
2∗(2x−1)
⇒2^{2x+1} = 2^{4x-2}2
2x+1
=2
4x−2
Since bases are equal powers are also equal
⇒2x+1 = 4x-2
⇒ 3 = 4x - 2x
⇒ 2x = 3
⇒ x = 3/2
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