Question

ii) x ^ 2 + 2x + 143 = 0 (Quadratic formula method)

Answer 1

Answer

x 2 -2x-143=0

⇒x 2 −13x+11x−143=0

⇒x(x−13)+11(x−13)=0

⇒(x−13)(x+11)=0

∴x=−11,13

Hope it helps

Plz mark as brain list

Answer 2

Step-by-step explanation:

if your question is this then the answer is

${x}^{2} + 2x + 143 = \\ \alpha \: and \: \beta = \frac{ - b \: plus \: or \: mius \: \sqrt{ {b}^{2} - 4ac } \: }{2a} \\ = \frac{ - 2 \: plus \: or \: minus \: \sqrt{ {2}^{2} - 4(143)} }{2} \\ = \frac{ - 2 \: plus \: or \: minus \: 2 \sqrt{142} }{2} \\ = - 1 \: plus \: or \: minus \: \sqrt{142}$

alpha is -1 - root 142

Beta is -1+ root 142

pls mark as brainlist

hope it helps you