Question

ii. x + 2y – 3z, – 3x + y + 2z and 2x – 3y + z​

Answer 1

Answer:

x —3x +2x + 2y + y —3y—3z +2z + z

—2x+2x +3y —3y—z +z

0+0+0=0

Answer 2

Answer:

• (x+2y-3z)-(-3x+y+2z)-(2x-3y+z)
• (x+2y-3z+3x+y+2z-2x+3y-z)
• (x+3x-2x+2y+y+3y-3z+2z-z)
• 2x+6y

2(x+3)

From adding

(x+2y-3z)+(-3x+y+2z)+(2x-3y+z)

• (x+2y-3z-3x+y+2z+2x-3y+z)
• -2x+2x+3y-3y-z+z
• 0