Question

(ii) x2 – 2kx + 7k - 12 = 0.​

Answer 1

Answer:

X2-2kx+7k-12=0

A = 1 , b = -2k , c = 7k-12

d = b^2 - 4ac

= 4k^2 - 4 × 1 × 7k-12

= 4k^2 - 28k + 48=0

= k^2 - 7k + 12 = 0

= (k-4) (k-3) = 0

= k = 4 , k = 3

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