Question

:
(ii) x2 - 2x = (-2) (3 - x)
(iv) (x - 3)(2x +1) = x(x + 5)
(vi) x2 + 3x + 1 = (x - 2)2
(viii) x3 - 4x2 - x + 1 = (x - 2)​

Answer 1

Step-by-step explanation:

(ii) x2 - 2x = (-2)(3-x)

0 = -6 + 2x

6 = 2x

6/2 = x

3 = x

(iv) (x - 3)(2x +1) = x(x + 5)

2x² + 1x -6x -3 = x² + 5x

2x² - x² -5x -5x -3 = 0

x² - 10x -3 = 0

(vi) x2 + 3x + 1 = (x - 2)2

5x +1 = 2x - 4

5x - 2x = -4 -1

3x = -5

x = -5/3

(viii) x3 - 4x2 - x + 1 = (x - 2)

x3 - 8x - x + 1 = x-2

x3 - 9x - x = - 2 - 1

X3 - 10x = - 3

-7x = - 3

7x = 3

x = 3/7

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