ii) (x² – 2xy + y^2) - z^2
Please solve the problem fast
Answers
Answered by
0
Answer:
(x
2
−2xy+y
2
)−z
2
⇒[x(x−y)−y(x−y)]−z
2
⇒(x−y)(x−y)−z
2
⇒(x−y)
2
−z
2
⇒[(x−y)+z][(x−y)−z]
⇒(x−y+z)(x−y−z)
Answered by
1
Answer:
here is your answer
x(x−y)−y(x−y)]−z²
⇒(x−y)(x−y)−z²
⇒(x−y)²-z²
⇒[(x−y)+z][(x−y)−z]
⇒(x−y+z)(x−y−z)
hopefully it helps you
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