Math, asked by rahulkumar1069, 11 months ago

(ii) x2 – 3x2 - 9x - 5
(iv) 2y + y2 - 2y - 1​

Answers

Answered by mysticd
10

ii) -3x²-9x-5

= (1-3)-9x-5

= -2x²-9x-5

= -(2x²+9x+5)

ii) 2y+-2y-1

= +2y-2y-1

= -1

= -1²

= (y+1)(y-1)

/* By algebraic identity:

-b² = (a+b)(a-b)

Answered by Razz005
3

Answer:

ii)x2-3x2-9x-5

3x2-x2-9x-5

3-9x-5

3-5-9x

2-9x (ans)

iv)2y+y2-2y-1

2y-2y+y2-1

0+y2-1

y2-1(ans)

hope that helps..

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