Question

(ii) x2 - (k + 4)x + 2k +5=0​

Answer 1

Answer:

k= 2(or)-2

Step-by-step explanation:

let us consider the nature of roots as real and equal

so, b2-4ac=0

(-k-4)^2-4(1)(2k+5)=0

k2+16+2(4)(k) -8k-20=0

k2+16+8k-8k-20=0

k2+16-20=0

k2-4=0

k2=4

k=√4

k=2(or)-2