Question

(ii) (y - 4) (2y +3y)​

Answer 1

Answer:

(y-4) (2y+3y)

2y^2+3y^2-8y-12y

5y^2-20y=0

5y(y-4)=0

either, 5y=0

y=0

or,. y-4=0

y=4

Answer 2

Answer:

y=4

Step-by-step explanation:

(Y-4)*(2y+3y)=(Y-4)*5y (Adding 3y and 2y)

                    =5y²-20y(Mutiplying y-4 with 5y)

            +20y=5y² (Cancelling one y on both sides)

                20=5y (dividing 20 by5)

                   y=20/5

                   y=4