Question

iif alfha and beata are zeroes of x2+5x+8 then the value alfha + beata​

Answer 1

Step-by-step explanation:

$\alpha + \beta = - b \div a$

in this equation

a=1, b= 5 c= 8

So,

$\alpha + \beta = - 5$

Answer 2

$\: \: \: \: \: \: \: \: \: \: \: \: \: {x}^{2} + 5x + 8 = 0$

• a = 1
• b = 5
• c = 8

$\: \: \: \sf \blue{sum \: of \: zeroes( \alpha + \beta ) = - \frac{b}{a} }$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = > \green{ \sf{\frac{ 5}{1} }}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \red {= > 5}$