Question

iif p(x)=xsquare -8then find the value of log base 10p(3)​

Answer 1

Step-by-step explanation:

p(X)=x^2-8

p(3)= 9-8

p(3)=1

a/q

$log_{10}p(3)$

$log_{10}(1)$

10^y=1

y = 0 because 10 to the power 0 = 1

final answer is 0

(this will definitely help u)