IIf theta=30° prove that tan2theta=2tantheta/1-tan²theta
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Step-by-step explanation:
theta=30°
LHS=tan2theta
=tan2.30
=tan60
=√3
RHS=2tan30/1-tan²30
=2.(1/√3)/1-1/3
=(2/√3)/(2/3)
=2/√3×3/2
=3/√3
=√3
LHS=RHS
So,tan2θ=2tanθ/1-tan²θ
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