iIfM-N-P and d (M. N) 15 and d (M, P) = 2S then find d (N, P)
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Answer:
If we know that ΔDEF∼ΔMNK
Then
MN
DE
=
NK
EF
=
KM
FD
=
Area(ΔMNK)
Area(ΔDEF)
It is given that DE=2,MN=5
Therefore,
MN
DE
=
Area(ΔMNK)
Area(ΔDEF)
=
5
2
⇒
Area(ΔMNK)
Area(ΔDEF)
=(
5
2
)
2
=
25
4
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