Question

iii) (1+w)3–(1+w2)3 = 0)​

Answer 1

Answer:

$1 + w = - {w}^{2} \\ \\ 1 + {w}^{2} = - w \\ \\ { (- {w}^{2}) }^{3} - {( { - w}^{}) }^{3} = {w}^{6} - {w}^{3} = 1 - 1 = 0$

Answer 2

Answer:

(1+w)^3-(1+w^2)^3

= (-w^2)^3-(-w) ^3

= -w^6-(-w^3)

=-(w^3)^2+w^3

=-(1)^2+1

=-1+1

=0

Step-by-step explanation:

w. ^3=1