(iii) 10xy (14y2 + 43y - 21) ÷5x(7y - 3)
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Answer:
10xy(14
y
2+43y−21)÷5x(7x−3)
=
5x(7y−3)
10xy[14y
2
+49y−6y−21]
=
5x(7y−3)
10xy[7y(2y+7)−3(2y+7)]
⎩
⎪
⎪
⎨
⎪
⎪
⎧
∵−21×14=−294
∴−249=49×(−6)
43=49−6
⎭
⎪
⎪
⎬
⎪
⎪
⎫
=
5x(7y−3)
10xy(2y+7)(7y−3)
=2xy(2y+7)
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