Math, asked by shyamuyadav1975, 5 months ago

(iii) 10xy (14y2 + 43y - 21) ÷5x(7y - 3)

Answers

Answered by srirammeghana

2

Answer:

10xy(14

y

2+43y−21)÷5x(7x−3)

=

5x(7y−3)

10xy[14y

2

+49y−6y−21]

=

5x(7y−3)

10xy[7y(2y+7)−3(2y+7)]

⎩

⎪

⎪

⎨

⎪

⎪

⎧

∵−21×14=−294

∴−249=49×(−6)

43=49−6

⎭

⎪

⎪

⎬

⎪

⎪

⎫

=

5x(7y−3)

10xy(2y+7)(7y−3)

=2xy(2y+7)

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