Question

iii) 16x' + 8x² +1 answer in square root​

Answer 1

Answer:

answer is 4x+1

Step-by-step explanation:

firstly simplifying the expression:

16 {x}^{4} + 8 {x}^{2} + 116x

4

+8x

2

+1

{(4x)}^{2} + 2 \times 4x \times 1 + {1}^{2}(4x)

2

+2×4x×1+1

2

we know that:

a^2+2ab+b^2=(a+b)^2

so it can be written as:

{(4x + 1)}^{2}(4x+1)

2

now finding square root of it,we get

\sqrt{ {(4x + 1)}^{2} }

(4x+1)

2

= 4x + 1=4x+1