Question

(iii) (√2a + √3b)² find the square using the identity​

Answer 1

Answer:

   =2a² + 2√6ab + 3b²

Step-by-step explanation:

using (a + b)² = a² + 2ab + b² identity,

we have,

      = ($\sqrt{2}$a)² + 2(√2a )  ( √3b) + (√3b)²

     =2a² + 2√6ab + 3b²

Answer 2

$( \sqrt{2} a + \sqrt{3} b) {}^{2}$

• $\bf\red{\implies} ( \sqrt{2} a) {}^{2} + ( \sqrt{3} b) {}^{2} + (2×\sqrt{2}a×\sqrt{3}b)$

• $\bf\red{\implies 2 a{}^{2} + 3 b {}^{2} + 2ab√6}$