Question

(iii) 3 (y + 3) + 2 = 4 (iv) 2 = 4 (2+4) (v) 6 = 3 (b-4) (vi) 3 (y + 3) + 4 = 28 y-2 (vii) 2 NT = 3 Exerolse 4.2 1) Form new equations by carrying out the action (given in brackets) on both sides of the equation (1) 2x + 3 = 13 (Multiply by 2) (10) 3y-3-21 (Add 5) (iii) 5x + 14 = 24 (Subtract 6) (iv) 10y +6 +36 (Divide by 2) (V) 5 + 4x=21 (Multiply by 3) (vi) 8 + 7x = 29 (Subtract 4) 2) Solve each of the following equations and check your solution by substituting its value in the equation. (i) 6 = 3(0 - 3) (ii) 6 = 4x - 2 3a-7 -- 4 (viii) 4 (ix) 3(b + 4) - 7= 4b + 14 (x) 4(x + 2) = -5(x + 2) 4x = -3(2-x) 2 - 4(3-y) =3(3+y) 2. (xi) (xii)​

Answer 1

1) 2x+3=13

2x=13 -3

2x=10

x=10/2=5 x2=10