(iii) 3x - 5y=16; x-3y=8
(v) 2x + 3y+4 = 0; x- 5y = 11
Answers
Answer:
HELLO EVERYONE,
(iii) 3x-5y=16;x-3y=8
we have,
3x-5y=16 equation 1.
x-3y=8 equation 2.
equation 2.multiply by 3
3x-9y=24 equation 4.
subtract equation 1. and equation 3.
3x-5y=16
3x-9y=24
- + -
________
4y=-8
________
y=-2
put the value of y in equation 2.
x-3y=8
x-3(-2) =8
x+6=8
x=8-6
x=2
so, x=2, y=-2
v) 2x+3y+4=0;x-5y=11
2x+3y=-4 equation 1.
x-5y=11 equation 2.
equation 2.multiply by 2
2x-10y=22 equation 3.
subtract equation 1.and 3.
2x+3y=-4
2x-10y=22
- + -
________
13y=-26
________
y=-2
put the value of y in equation 2.
x-5y=11
x-5(-2) =11
x+10=11
x=11-10
x=1
so, x=1, y=-2
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Answer:
x= 2 y= -2
Step-by-step explanation:
3x - 5y = 16 (1)
x - 3y = 8 (2)
Multiplying eqn. (2) by 3
3x - 9y = 24 (3)
Subtracting equation (1) from (3)
3x - 9y = 24
- 3x - 5y = 16
(-) (+) (-)
= -4y = 8
y = 8/-4
y = -2
Substituting y = -2 in equation (2)
x - 3y = 8
x - 3(-2) = 8
x + 6 = 8
x = 8 - 6
x = 2
( x , y ) = ( 2 , -2 )