Question

(iii) (4x-3)2-2(x+3)=0​

Answer 1

$\huge\fbox\orange{SOLUTION}$

(4x-3)2-2(x+3)=0

→ 8x-6-2x-6=0

→ 6x-12=0

→ 6x= 12

→ x= 12/6

→ x= 2

$\huge\red{@MizZHarami}$

Answer 2

$\huge\fbox\pink{@ItzZSiddhi}$

→ (4x-3)2-2(x+3)=0

→ 8x-6-2x-6=0

→ 6x-12=0

→ 6x=12

→ x=12/6

→ x=2