Question

(iii) 62^n+1 = 36 = 6^3​

Answer 1

Answer:

Heya!

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♦Given that =>

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\begin{gathered} = > \frac{6 {}^{2n + 1} }{36} = 6 {}^{3} \\ \\ = > \frac{6 {}^{2n + 1} }{6 {}^{2} } = 6 {}^{3} \\ \\ = > 6 {}^{2n + 1 - 2} = 6 {}^{3} \\ \\ = > 6 {}^{2n - 1} = 6 {}^{3} \\ \\ = > putting \: powers \: eq. \: since \: base \: is \: same \\ \\ = > 2n - 1 = 3 \\ \\ = > 2n = 4 \\ \\ = > n = 2\end{gathered}

=>

36

6

2n+1

=6

3

=>

6

2

6

2n+1

=6

3

=>6

2n+1−2

=6

3

=>6

2n−1

=6

3

=>puttingpowerseq.sincebaseissame

=>2n−1=3

=>2n=4

=>n=2