Question

iii) 6m2 + m = 2 solve by sq. method ​

Answer 1

6m²+m=2

6m²+m-2=0

first multiply 6m²×2,we get 12

and then find the factors of 12 whose difference is 1

4×3 =12,so 4 and 3 are the factors of 12 whose difference is 1

so,

6m²+m-2=0

6m²+(4-3)m-2=0

6m²+4m-3m-2=0

2m(3m+2)-1(3m+2)=0

(3m+2)(2m-1)=0

3m+2=0

m=-2/3

OR

2m-1=0

m=1/2

Answer 2

Answer:

ur answer is 1/2.........