(iii) (a-2b+5c)(a-b)-(a-b-c)(2a+3c)+(6a+b)(2c-3a-5b)
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We solve the given expression (a−2b + 5c)(a−b)−(a−b−c)(2a + 3c) + (6a + b)(2c−3a−5b) (a−2b + 5c)(a−b)−(a−b−c)(2a + 3c) .
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