Question

iii. A body is in the state of motion having mass 50 kg.with a velocity 10 m/s, if it
reaches its destinations in 5 secs. What is its Power?​

Answer 1

Explanation:

ANSWER

For a perfectly elastic collision, coefficient of restitution is e=1.

Let u and v be the velocities of 10 kg and 1 g masses after collision.

Thus, e=

rel. vel. of approach

rel. vel.of separation

=

$\frac{5 - o}{v - u}$

$\frac{ 0}{v - u}$

But, as e=1, we have v−u=5.

Total momentum before collision is P=10×5=50 kg m/s

Total momentum after collision is P=10×(v−5)+0.001×v=10.001v−50

Thus, 10.001v−50=50⇒v=

$\frac{100}{10.001}$

≈10 m/s